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A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from x = 0 to x = 6 m is
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- 18.0 J
- 13.5 J
- 9.0 J
- 4.5 J
Correct Option: B
Work done = area under F-x graph
= area of trapezium OABC
| = | (3 + 6)(3) = 13.5 J | |
| 2 |
