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A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms–1. It collides with a horizontal spring of force constant 200 Nm–1. The maximum compression produced in the spring will be :
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- 0.5 m
- 0.6 m
- 0.7 m
- 0.2 m
Correct Option: B
At maximum compression the solid cylinder will stop so loss in K.E. of cylinder = gain in P.E. of spring
⇒ | mv2 + | Iω2 = | kx2 | |||
2 | 2 | 2 |
⇒ | mv2 + | ![]() | ![]() | 2 | = | kx2 | |||||||
2 | 2 | 2 | R | 2 |
⇒ | mv2 = | kx2 | ||
4 | 2 |
⇒ | × 4 × (4)2 = | × 200 x2 | ||
4 | 2 |
⇒ | = x2 ⇒ x = 0.6 m | |
100 |