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  1. A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms–1. It collides with a horizontal spring of force constant 200 Nm–1. The maximum compression produced in the spring will be :​​
    1. 0.5 m
    2. 0.6 m
    3. 0.7 m
    4. 0.2 m
Correct Option: B

At maximum compression the solid cylinder will stop so loss in K.E. of cylinder = gain in P.E. of spring

1
mv2 +
1
2 =
1
kx2
222

1
mv2 +
1
mR2
v
2 =
1
kx2
222R2

3
mv2 =
1
kx2
42

3
× 4 × (4)2 =
1
× 200 x2
42

36
= x2 ⇒ x = 0.6 m
100



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