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A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to mass of 3m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is
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1 vî - 3 vĵ 4 2 -
1 vî + 2 vĵ 3 3 -
2 vî + 1 vĵ 3 3 -
3 vî + 1 vĵ 2 4
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Correct Option: A
As the two masses stick together after collision, hence it is inelastic collision. Therefore, only momentum is conserved.
∴ mvî + 3m(2v)ĵ = (4m)v→
v→ = | î + | vĵ | ||
4 | 4 |
= | î + | vĵ | ||
4 | 2 |