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A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and
then adiabatically to a volume 16V. The final pressure of the gas is : (take γ = 5 ) 3
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- 64P
- 32P
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P 64 - 16 P
Correct Option: C
For isothermal process P1V1 = P2V2
⇒ PV = P2(2V) ⇒ P2 = | ||
2 |
For adiabatic process
P2V2γ = P3V3γ
⇒ | ![]() | ![]() | (2v)γ = (P316v)γ | |
2 |
⇒ P3 = | ![]() | ![]() | 5 / 3 | = | |||
2 | 8 | 64 |