-
A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are
PA = 3 × 104 Pa
VA = 2 × 10-3 m3
PB = 8 × 104 Pa
VD = 5 × 10-3 m3.
In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be
-
- 560 J
- 800 J
- 600 J
- 640 J
Correct Option: A
Since AB is an isochoric process, so, no work is done. BC is isobaric process,
∴ W = PB × (VD – VA) = 240 J
∆Q = 600 + 200 = 800 J
Using ∆Q = ∆U + ∆W
⇒ ∆U = ∆Q – ∆W = 800 – 240 = 560 J
