An ideal carnot engine, whose efficiency is 40% receives

An ideal carnot engine, whose efficiency is 40% receives heat at 500 K. If its efficiency is 50%, then the intake temperature for the same exhaust temperature is

Efficiency of carnot engine (η₁) = 40% = 0.4;
Initial intake temperature (T₁) = 500K and new efficiency (η₂) = 50% = 0.5.

Efficiency , η = 1 -	T₂	or	T₂	= 1 - η
	T₁		T₁

Therefore in first case,	T₂	= 1 - 0.4 = 0.6
	500

⇒ T₂ = 0.6 × 500 = 300K

And in second case ,	300	= 1 - 0.5 = 0.5
	T₁

⇒ T₁ =	300	= 600 K
	0.5