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Two simple harmonic motions of angular frequency 100 and 1000 rad s–1 have the same displacement amplitude. The ratio of their maximum accelerations is :
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- 1 : 10
- 1 : 102
- 1 : 103
- 1 : 104
Correct Option: B
Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency
i.e. a ∝ ω2
| ∴ | = | = | = | |||||
| a2 | ω22 | (1000)2 | 100 |
⇒ a1 : a2 = 1 : 102.
