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A particle is executing a simple harmonic motion of amplitude a. Its potential energy is maximum when the displacement from the position of the maximum kinetic energy is
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- 0
- -a
- a / 2
- – a / 2
Correct Option: B
| P.E. of particle executing S.H.M. = | mω2 x2 | |
| 2 |
| At x = a, P.E. is maximum i.e. = | mω2 a2 | |
| 2 |
At x = 0, K.E. is maximum. Hence, displacement from position of maximum Kinetic energy = a.
