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The angular velocity and the amplitude of a simple pendulum is ω and a respectively. At a displacement x from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is
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(a2 - x2 ω2) x2 ω2 -
x2 ω2 (a2 - x2 ω2) -
(a2 - x2) x2 -
x2 (a2 - x2)
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Correct Option: C
P.E. , V = | mω2 x2 | |
2 |
and K.E., T = | mω2(a2 - x2) | |
2 |
∴ | = | |||
V | x2 |