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A particle is executing a simple harmonic motion. Its maximum acceleration is a and maximum velocity is b.Then its time period of vibration will be :
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α β -
β2 α -
2πβ α -
β2 α2
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Correct Option: C
As, we know, in SHM
Maximum acceleration of the particle, α = Aω2
Maximum velocity, β = Aω
| ⇒ ω = | ||
| β |
| T = | - |  | ∵ |  | ||||
| ω | α | T |
