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A point performs simple harmonic oscillation of period T and the equation of motion is given by x = a sin (ωt + π/6). After the elapse of what fraction of the time period the velocity of the point will be equal to half of its maximum velocity?
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- T/8
- T/6
- T/3
- T/12
Correct Option: D
| We have , x = a sin | ![]() | ωt + | ![]() | ||
| 6 |
| ∴ Velocity , v = | = aω cos | ![]() | ωt + | ![]() | |||
| dt | 6 |
Maximum velocity = aω
According to question,
| = aω cos | ![]() | ωt + | ![]() | ||||
| 2 | 6 |
| or cos | ![]() | ωt + | ![]() | = | = cos 60° or cos | |||
| 6 | 2 | 3 |
| ⇒ ωt + | = | ||
| 6 | 3 |
| ⇒ ωt = | - | or ωt = | |||
| 3 | 6 | 6 |
| or | .t = | ⇒ t = | |||
| T | 6 | 12 |

