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A point performs simple harmonic oscillation of period T and the equation of motion is given by x = a sin (ωt + π/6). After the elapse of what fraction of the time period the velocity of the point will be equal to half of its maximum velocity?
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- T/8
- T/6
- T/3
- T/12
Correct Option: D
We have , x = a sin | ![]() | ωt + | ![]() | ||
6 |
∴ Velocity , v = | = aω cos | ![]() | ωt + | ![]() | |||
dt | 6 |
Maximum velocity = aω
According to question,
= aω cos | ![]() | ωt + | ![]() | ||||
2 | 6 |
or cos | ![]() | ωt + | ![]() | = | = cos 60° or cos | |||
6 | 2 | 3 |
⇒ ωt + | = | ||
6 | 3 |
⇒ ωt = | - | or ωt = | |||
3 | 6 | 6 |
or | .t = | ⇒ t = | |||
T | 6 | 12 |