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Masses MA and MB hanging from the ends of strings of lengths LA and LB are executing simple harmonic motions. If their frequencies are fA = 2fB, then
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- LA = 2LB and MA = MB/2
- LA = 4LB regardless of masses
- LA = LB/4 regardless of masses
- LA = 2LB and MA = 2MB
Correct Option: C
| fA = |  |  | ||
| 2π | LA |
| and fB = | = | | | |||
| 2 | 2π | LB |
| ∴ | = | | | × 2π | | | |||
| fA / 2 | 2π | LA | LB |
| ⇒ 2 = | | | ⇒ 4 = |
| , regardless of mass. | |||
| LB | LA |
