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Suppose the charge of a proton and an electron differ slightly. One of them is – e, the other is (e + ∆e). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then ∆e is of the order of [Given mass of hydrogen mh = 1.67 × 10–27 kg]
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- 10–23 C
- 10–37 C
- 10–47 C
- 10–20 C
Correct Option: B
According to question, the net electrostatic force (FE) = gravitational force (FG)
FE = FG
| or | = | |||||
| 4πε0 | d2 | d2 |
| ⇒ ∆e = m |  | |
| K |
| ∵ |  | = k = 9 × 109 |  | |
| 4πε0 |
| = 1.67 × 10–27 | | |
| 9 × 109 |
∆e ≈ 1.436 × 10–37 C
