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A charge ‘q’ is placed at the centre of the line joining two equal charges ‘Q’. The system of the three charges will be in equilibrium if ‘q’ is equal to
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- Q/2
- – Q/4
- Q/4
- – Q/2
Correct Option: B
The system of three charges will be in equilibrium.
For this, force between charge at A and B + force between charge at point O and either at A or B is zero.
i.e. , | + | = 0 | ||
r2 | (r / 2)2 |
By solving we get,
q = - | ||
4 |