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A point source of light is placed 4 m below the surface of water of refractive index 5 . 3
The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut off all light coming out of water is
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- ∞
- 6 m
- 4 m
- 3 m
Correct Option: B
sin C = | = | = | ⇒ tan C = | ||||||
μ | 5 | 4 | |||||||
3 |
Now, tan C = | ; r = h tan C = 4 × | = 3 m | ||
h | 4 |
Diameter of disc = 2r = 6 m