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The wavelength associated with an electron, accelerated through a potential difference of 100 V, is of the order of
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- 1000 Å
- 100 Å
- 10.5 Å
- 1.2 Å
Correct Option: D
Potential difference = 100 V
K.E. acquired by electron = e (100)
| mv2 = e(100) | 2 |
| ⇒ v = |  | |
| m |
According to de Broglie's concept
| λ = | mv |
| ⇒ λ = | |||
| m | | ||
| m | |||
| = | = 1.2 × 10-10 = 1.2Å | √2me(100) |
