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An ionization chamber with parallel conducting plates as anode and cathode has 5 × 107 electrons and the same number of singly charged positive ions per cm3. The electrons are moving towards the anode with velocity 0.4 m/s. The current density from anode to cathode is 4μA/m2. The velocity of positive ions moving towards cathode is
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- 0.4 m/s
- 1.6 m/s
- zero
- 0.1 m/s
Correct Option: D
Current = Ie + Ip
Ie and Ip are current due to electrons and positively charged ions.
I = neAVd
[ n = 5 × 107 /cm3 = 5 × 107 × 106 / m3 = 5 × 1013/m3 ]
Ie = 5 × 1013 × 1.6 × 10-19 × A × 0.4
Ip = 5 × 1013 × 1.6 × 10-19 × A × v
I = Ie + Ip
= 5 × 1013 × 1.6 × 10-19 × A (v + 0.4)
Given,
I/A = 4 × 10-6 A/m2
4 × 10-6 A =5 × 10-6 × 1.6 × A (v + 0.4)
= v + 0.4 | 8 |
⇒ 0.5 = v + 0.4 ⇒ v = 0.1 m/s