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For photoelectric emission from certain metal the cut-off frequency is ν. If radiation of frequency 2ν impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
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- √ hv/m
- √ 2hv/m
- 2√ hv/m
- √ hv/(2m)
Correct Option: B
From photo-electric equation,
hν' = hν +
Kmax ...(i)
h.2v = hv + | mV2max | 2 |
[∴ v' = 2v]
⇒ hv = | mV2max | 2 |
⇒ vmax = | ||
m |