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A 200 W sodium street lamp emits yellow light of wavelength 0.6 µm. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is
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- 1.5 × 1020
- 6 × 1018
- 62 × 1020
- 3 × 1019
Correct Option: A
Give that, only 25% of 200 W converter electrical energy into light of yellow colour
× N = 200 × | |||||||
λ | 100 |
Where N is the No. of photons emitted per second, h = plank’s constant, c, speed of light.
N = | × | |||
100 | hc |
= | 1.5 × 1020 | 100 × 6.2 × 10-34 × 3 × 108 |