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Dual Nature of Radiation and Matter

  1. In a photo-emissive cell, with exciting wavelength λ, the fastest electron has speed v. If the exciting wavelength is changed to 3λ/4 , the speed of the fastest emitted electron will be
    1. (3/4)1/2. v
    2. (4/3)1/2. v
    3. less than (4/3)1/2. v
    4. greater than (4/3)1/2. v
Correct Option: D

1
mv2 =
hc
- W0
2λ

or
hc
=
1
mv2 + W0
λ2

and
1
mv21 =
hc
- W0
2(3λ/4)

1
1
mv2 + W0 - W0
42

So, v1 is greater than
v1 =
4
1/2
3



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