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In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width
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- is doubled
- is halved
- becomes four times
- remains unchanged
Correct Option: C
Fringe width
| β = | d |
From question D′ = 2D
| and d' = | 2 |
| β' = | = 4β | d1 |
