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In Young’s double slit experiment carried out with light of wavelength (λ ) = 5000 Å, the distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0. The third maximum (taking the central maximum as zeroth maximum) will be at x equal to
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- 1.67 cm
- 1.5 cm
- 0.5 cm
- 5.0 cm
Correct Option: B
| x = (n)λ | = 3 × 5000 × 10-10 × | |||
| d | 0.2 × 10-3 |
= 1.5 × 10-2 m = 1.5 cm
