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A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is 4 × 10–3 Wb. The self inductance of the solenoid is :
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- 4H
- 3H
- 2H
- 1H
Correct Option: D
Here, number of turns n = 100; current through the solenoid i = 4A; flux linked with each turn = 4 × 10–3 Wb
∴ Total flux linked, and total
= 1000[4 × 10–3] = 4 Wb
φtotal = 4 ⇒ L i = 4
⇒ L = 1 H