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Preeti reached the metro station and found that the escalator was not working. She walked up the stationary escalator in time t1. On other days, if she remains stationary on the moving escalator, then the escalator takes her up in time t2. The time taken by her to walk up on the moving escalator will be:
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t1t2 t2 - t1 -
t1t2 t2 + t1 - t1 - t2
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t1 + t2 2
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Correct Option: B
| Velocity of preeti w.r.t. elevator v1 = | |
| t1 |
| Velocity of elevator w.r.t. ground then velocity of preeti w.r.t. ground v2 = | |
| t2 |
v = v1 + v2
| = | + | ||||
| t | t1 | t2 |
| = | + | ||||
| t | t1 | t2 |
| ∴ t = | (time taken by preeti to walk up on the moving escalator) | |
| (t1 + t2) |
