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If the velocity of a particle is v = At + Bt², where A and B are constants, then the distance travelled by it between 1s and 2s is :
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3 A + 4B 2 - 3A + 7B
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3 A + 7 B 2 3 -
A + B 2 3
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Correct Option: C
Given : Velocity
V = At + Bt² ⇒ dx/dt = At + Bt²
By integrating we get distance travelled
Distance travelled by the particle between 1s and 2s
X = | (2² - 1²) + | (2³ - 1³) = | + | ||||
2 | 3 | 2 | 3 |