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The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement of the particle when its velocity is zero, will be
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- 2 m
- 4 m
- zero
- 6 m
Correct Option: C
∵ t = √x - 3
⇒ √x = t – 3 ⇒ x = (t – 3)²
v = dx/dt = 2(t – 3) = 0
⇒ t = 3
∴ x = (3 – 3)²
⇒ x = 0.
