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A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S1 and that covered in the first 20 seconds is S2, then:
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- S2 = 3S1
- S2 = 4S1
- S2 = S1
- S2 = 2S1
Correct Option: B
u = 0, t1 = 10s, t2 = 20s
Using the relation, S = ut + 1/2 at²
Acceleration being the same in two cases,
S1 = (1/2)a × t1², S2 = (1/2)a × t2²
∴ S1/S2 = (t1/t2)² = (10/20)² = 1/4
S2 = 4S1
