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  1. If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is​​​
    1. ​(u + gt) t
    2. ut
    3. 1/2 gt²
    4. ut - 1/2 gt²
Correct Option: C

Let body takes T sec to reach maximum height.
Then v = u – gT
v = 0, at highest point. T = u/g …(1)
Velocity attained by body in (T – t) sec v = u – g (T – t)

= u – gT + gt = u – g
u
+ gt
g

or v = gt …(2)

∴ Distance travelled in last t sec of its ascent
s = (gt)t -
1
gt² =
1
gt²
22



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