Two discs of same moment of inertia rotating about their

Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities ω₁ and ω₂ . They are brought into contact face to face coinciding the axis of rotation. The expression for loss of energy during this process is:-

Here, lω₁ + lω₂ = 2lω

⇒ ω =	ω₁ + ω₂
	2

(K.E)_i =	1	lω₁² +	1	lω₂²
	2		2

(K.E)_f =	1	2lω² = T		ω₁ + ω₂		²
	2			2

Loss in K.E. = (K.E)_f - (K.E)_i = (1/4) l(ω₁ - ω₂)²

1	I(ω₁ - ω₂)²
4

1	I(ω₁ - ω₂)²
8

1	I(ω₁ - ω₂)²
2