-
One mole of an ideal diatomic gas undergoes undergoes a transition from A to B along a path AB as shown in the figure.
The change in internal energy of the gas during the transition is:
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- – 20 kJ
- 20 J
- –12 kJ
- 20 kJ
Correct Option: A
Change in internal energy from A → B
∆U = | nR∆T = | nR (Tf – Ti) | {PfVf – PiVi} | |||
2 | 2 | 2 |
(As gas is diatomic ∴ f = 5)
= | {2 × 10³ × 6 – 5 × 10³ × 4} | |
2 |
= | {12 - 20} × 10³J = 5 × (-4) × 10³J | |
2 |
∆U = - 20KJ