The degree of freedom of a molecule of a triatomic gas is
2
4
6
8
Correct Option: C
No. of degree of freedom = 3 K – N where K is no. of atom and N is the number of relations between atoms. For triatomic gas, K = 3, N = ³C2 = 3 No. of degree of freedom = 3 (3) – 3 = 6