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A star, which is emitting radiation at a wavelength of 5000 Å, is approaching the earth with a velocity of 1.50 × 106 m/s. The change in wavelength of the radiation as received on the earth is
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- 0.25 Å
- 2.5 Å
- 25 Å
- 250 Å
Correct Option: C
Given : Wavelength (λ) = 5000 Å
velocity of star (v) = 1.5 × 106 m/s.
We know that wavelength of the approaching star (λ')
(λ') = λ | ||
c |
or, | = | = 1 - | |||
λ | c | c |
or, | = 1 - | = | = | ||||
c | λ | λ | λ |
Therefore,
Δλ = λ × | = 5000 × | = 25 Å | ||
c | 3 × 10 × 108 |
[where ∆λ = Change in the wavelength]