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Physics of Sound

  1. A star, which is emitting radiation at a wavelength of 5000 Å, is approaching the earth with a velocity of 1.50 × 106 m/s. The change in wavelength of the radiation as received on the earth is
    1. 0.25 Å
    2. 2.5 Å
    3. 25 Å
    4. 250 Å
Correct Option: C

Given : Wavelength (λ) = 5000 Å
velocity of star (v) = 1.5 × 106 m/s.
We know that wavelength of the approaching star (λ')

(λ') = λ
c - v
c

or,
λ'
=
c - v
= 1 -
v
λcc

or,
v
= 1 -
λ'
=
λ - λ'
=
Δλ
cλλλ

Therefore,
Δλ = λ ×
v
= 5000 ×
1.5 × 106
= 25 Å
c3 × 10 × 108

[where ∆λ = Change in the wavelength]



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