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If potential (in volts) in a region is expressed as V(x, y, z) = 6 xy – y + 2yz, the electric field (in N/C) at point (1, 1, 0) is :
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- -(6î + 5ĵ + 2̂k
- -(2î + 3ĵ + ̂k
- -(6î + 9ĵ + ̂k
- -(3î + 5ĵ + 3̂k
Correct Option: A
Potential in a region
V = 6xy – y + 2yz As
we know the relation between electric potential and electric field is →E = -dV/dX
→E = | ![]() | î + | ĵ + | ̂k | ![]() | |||
∂x | ∂y | ∂z |
→E = [(6y î + (6x - 1 + 2z)ĵ + (2y)̂k]
→E(1,1,0) = -( 6î + 5ĵ + 2̂k)