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In a region, the potential is represented by V(x, y, z) = 6x – 8xy – 8y + 6yz, where V is in volts and x, y, z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is :
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- 6√5N
- 30 N
- 24 N
- 4√35N
Correct Option: D
→E = - | î + | ĵ + | ̂k | |||
∂x | ∂y | ∂z |
= - [(6 - 8y)î + (-8X - 8 + 6z)ĵ + (6y)̂k]
At (1,1,1), →E(1,1,0) = 2î + 10ĵ - 6̂k
⇒ (→E) = √2² + 10² + 6² = √140 = 2√35
∴ F = q→E = 2 × 2√35 = 4√35