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Electrostatic Potential and Capacitance

  1. Three concentric spherical shells have radii a, b and c (a < b < c) and have surface charge densities, σ, – σ and σ respectively. If VA, VB and VC denotes the potentials of the three shells, then for c = a + b, we have
    1. VC = VB ≠ VA
    2. VC ≠ VB ≠ VA
    3. VC = VB = VA
    4. VC = VA ≠ VB
Correct Option: D

c = a + b. ​

VA =
σa
-
σb
+
σc
=
σ
[c - (b -a)]
ε0ε0ε0ε0

VB =
σc
-
1
.
σ × 4πb²
+
1
.
σ × 4πa²
ε04πε0c4πε0c

=
σ
c -
(b² - a²)
ε0c

=
σ
[c - (b - a)]
ε0

VA = VCB

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