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The electric potential at a point (x, y, z) is given by V = – x²y – xz³ + 4. The electric field ⇒E at that point is
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- ⇒E = î 2xy + ĵ (x² + y²) + ∆k(3xy - y²)
- ⇒E = î z³ - ĵ xyz - ∆k z²
- ⇒E = î (2xy - z³) + ĵxy² + ∆k 3z² x
- ⇒E = î (2xy + z³) + ĵx² + ∆k 3xy⊃
Correct Option: D
The electric field at a point is equal to negative of potential gradient at that point.
→E = | ![]() | î + | ĵ + | ̂k | ![]() | ||||
∂r | ∂x | ∂y | ∂z |
= [(2xy + z³ )î + ĵx² + ̂3xz²]