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Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that ‘O’ is their common point for the two. The wires carry I1 and I2 currents respectively. Point ‘P’ is lying at distance ‘d’ from ‘O’ along a direction perpendicular to the plane containing the wires. The magnetic field at the point ‘P’ will be :
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μ0 I1 2πd I2 -
μ0 (I1 + I2) 2πd -
μ0 (I1² - I2²) 2πd -
μ0 (I1² - I2²)1/2 2πd
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Correct Option: D
Net magnetic field, B = √B1² + √B2²
= | |||||||||
² | + | ² | |||||||
2πd | 2πd |
∵ B1 = | And B2 = | ||||
2πd | 2πd |
= | √I1² + I2² | |
2πd |