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An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current 'I' along the same direction is shown in fig. Magnitude of force per unit length on the middle wire 'B' is given by
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2μ0i² πd -
√2μ0i² πd -
μ0i² √2πd -
μ0i² 2πd
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Correct Option: C
Force per unit length between two parallel current carrying conductors,
| F = | ||
| 2πd |
Since same current flowing through both the wires
ii = i2 = i
| so F1 = | = F2 | |
| 2πd |
∴ Magnitude of force per unit length on the middle wire ‘B’
| Fnet = √F1² + F2² = | ||
| √2πd |
