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A astronomical telescope has objective and eyepiece of focal lengths 40 cm and 4 cm respectively. To view an object 200 cm away from the objective, the lenses must be separated by a distance :
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- 37.3 cm
- 46.0 cm
- 50.0 cm
- 54.0 cm
Correct Option: D
Given: Focal length of objective, f0 = 40cm
Focal length of eye – piece fe = 4 cm
image distance, v0 = 200 cm
Using lens formula for objective lens
- | = | ⇒ | = | - | |||||||
v0 | u0 | ƒ0 | v0 | ƒ0 | u0 |
⇒ | = | + | = | ||||
v0 | 40 | - 200 | 200 |
⇒v0 = 50 cm
Tube length ℓ = |v0| + fe = 50 + 4 = 54 cm.