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Ray Optics and Optical Instruments

  1. The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are :
    1. 10 cm, 10 cm
    2. 5 cm, 5 cm
    3. 18 cm, 2 cm
    4. 11 cm, 9 cm
Correct Option: C

M.P. = 9 =
ƒ0
ƒe

​⇒​ƒ0 = 9ƒe​​​​...(1) ​
ƒ0 + ƒe = 20​​​​...(2) ​
on solving ​
ƒ0 = 18 cm = focal length of the objective ​
ƒe = 2 cm = focal length of the eyepiece



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