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The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are :
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- 10 cm, 10 cm
- 5 cm, 5 cm
- 18 cm, 2 cm
- 11 cm, 9 cm
Correct Option: C
M.P. = 9 = | ||
ƒe |
⇒ƒ0 = 9ƒe...(1)
ƒ0 + ƒe = 20...(2)
on solving
ƒ0 = 18 cm = focal length of the objective
ƒe = 2 cm = focal length of the eyepiece