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A bar magnet, of magnetic moment M', is placed in a magnetic field of induction B'. The torque exerted on it is
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- M→ . B→
- - M→ . B→
- M→ × B→
- B→ × M→
Correct Option: C
We know that when a bar magnet is placed in the magnetic field at an angle θ, then torque acting on the bar magnet (τ) = MB sin θ = M→ × B→.
Note : This torque τ has a tendency to make the axis of the magnet parallel to the direction of the magnetic field.