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The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by
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- 2
- 1
- 0.5
- 0.25
Correct Option: A
Magnetic moment = M; Initial angle through which magnet is turned (θ1) = 90º and final angle through which magnet is turned (θ2)= 60º. Work done in turning the magnet through 90º(W1) = MB (cos 0º – cos 90º) = MB (1–0) = MB.
Similarly, W2 = MB (cos 0º – cos 60º)
∴W1 = 2W1 or n = 2.