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Four identical thin rods each of mass M and length l, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is:
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2 Ml² 3 -
13 Ml² 3 -
1 Ml² 3 -
4 Ml² 3
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Correct Option: D
Moment of inertia of a thin rod of length l about an axis passing through centre and perpendicular to the rod = (1/12)Ml²
Thus moment of inertia of the frame.
| + | = | = | |||||
| 12 | 4 | 12 | 3 |
Total M.I. = 4 × (ml²/3)
