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A thin rod of length L and mass M is bent at its midpoint into two halves so that the angle between them is 90°. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is:
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ML² 24 -
ML² 12 -
ML² 6 -
√2ML² 24
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Correct Option: B
Mass of each part = M/2
Length of each part = L/2
Total M.I. = Sum of M.I.s of both parts
= | ![]() | ![]() | ![]() | ![]() | ² | × | + | ![]() | ![]() | ![]() | ![]() | ² | × | ||||||||||
2 | 2 | 3 | 2 | 2 | 3 |
= 2 × | × | × | = | ||||
2 | 4 | 3 | 12 |