If a negligibly small current is passed through a wire of

If a negligibly small current is passed through a wire of length 15 m and of resistance 5Ω having uniform cross-section of 6 × 10–7 m2 , then coefficient of resistivity of material, is

Given : Length of wire (l) = 15m
Area (A) = 6 × 10^–7 m²
Resistance (R) = 5Ω.
We know that resistance of the wire material

R = ρ	l
	A

⇒ 5 = ρ ×	15	= 2.5 × 10^-7ρ
	6 × 10^-7

⇒ ρ =	5	= 2.5 × 10^-7Ω - m
	2.5 × 10^-7

[where ρ = coefficient of resistivity]