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If a wire of resistance R is melted and recasted to half of its length, then the new resistance of the wire will be
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- R / 4
- R / 2
- R
- 2R
Correct Option: A
Initial resistance (R1) = R; Initial length l1is 1and final length (l2) = 0.5 l . Volume of a wire = l . A. Since the volume of the wire remains the same after recasting, therefore l1. A1 = l2 A2
We also know that resistance of a wire (R)
R = ρ × | .; R ∝ | |||
A | A |
∴ | R1 | = | l1 | × | A2 | = | l | × 2 = 4 |
R2 | l2 | A1 | 0.5l |
or, R2 = | = | |||
4 | 4 |
[Alt : When wires are drawn from same volume but with different area of cross-section, then
R ∝ | 1 | |
(Area of cross-section)² |