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Current Electricity

  1. If a wire of resistance R is melted and recasted to half of its length, then the new resistance of the wire will be​​
    1. R / 4 ​
    2. R / 2 ​
    3. R ​
    4. 2R
Correct Option: A

Initial resistance (R1) = R; Initial length l1is 1and final length (l2) = 0.5 l . Volume of a wire = l . A.  Since the volume of the wire remains the same after recasting, therefore l1. A1 = l2 A2

We also know that resistance of a wire (R)

R = ρ ×
l
.; R ∝
l
AA

R1=l1 ×A2 = l × 2 = 4
R2l2A10.5l

or, R2 =
R1
=
R
44

[Alt : When wires are drawn from same volume but with different area of cross-section, then
R ∝1
(Area of cross-section)²



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