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A current of 3 amp flows through the 2Ω resistor shown in the circuit. The power dissipated in the 5-Ω resistor is:
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- 4 watt
- 2 watt
- 1 watt
- 5 watt
Correct Option: D
Clearly, 2Ω , 4Ω and ( 1 + 5) Ω resistors are in parallel. Hence, potential difference is same across each of them.
∴ I1 × 2 = I2 × 4 = I3 × 6
Given I1 = 3A
∴ I1 × 2 = I3 × 6
Given I1 = 3A.
∴ I1 × 2 = I3 × 6 provides
I3 = | I1 x 2 | = | 3 x 2 | = 1A |
6 | 6 |
Now, the potential across the 5Ω resistor is V = I3 × 5 = 1 × 5 = 5V.
∴ the power dissipated in the 5Ω resistor
P = | V² | = | 5² | = 5 Watt. |
R | 5 |