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A condenser of capacity C is charged to a potential difference of V1. The plates of the condenser are
then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to V2 is
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- [C(V12 - V22)/L]1/2
- [C(V1 - V2)²/L]1/2
- [C(V12 - V22)/L]
- [CV1 - V2)/L]
Correct Option: A
q = CV1 cos wt
⇒ i = | = - ω Cv1 sin ωt | |
dt |
Also, ω² = | and V = V1 cos ωt | |
LC |
At t = t1, V = V2 and i = -ω CV1 sinωt1
∴ cos ωt1 = | V2 | (–ve sign gives direction) |
V1 |
= {C(V12) - V22) / L}²