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Power dissipated in an LCR series circuit connected to an a.c source of emf ε is
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ε²√R² + [Lω - (1/Cω)]² R -
ε²[R² + Lω - (1/Cω)]² R -
ε²/R R² + [Lω - (1/Cω)]² -
ε²/R [R² + Lω - (1/Cω)]²
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Correct Option: D
Power dissipated in series LCR;
| P = I² R = | R | |
| (Z)² |
| = | ||
| [R² + (ωL -(1/ωC))²] |
Where Z = √R² + [ωL -(1 / ωC)]²
is called the impedance of the circuit.
