An enzyme converts substrate A to product B. At a given

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An enzyme converts substrate A to product B. At a given liquid feed stream of flow rate 25 L.min^–1 and feed substrate concentration of 2 mol.L^–1, the volume of continuous stirred tank reactor needed for 95% conversion willbe _____________ L.
Given the rate equation : – r_A = 0.1 C_A
1 + 0.5C_A

where – r_A is the rate of reaction in mol.L^–1.min^–1 and C_A is the substrate concentration in mol.L^–1
Assumptions : Enzyme concentration is contant and does not undergo any deactivation during the reaction.

1. 1986.0 to 1989.0
2. 986.0 to 989.0
3. 2443.0 to 2544.0
4. 4986.0 to 4989.0

Correct Option: D

For CSTR

(i)	V	=	C_AOX_A
(i)	v₀	=	r_A

Here , v₀ = 25 L/min
C_AO = 2 ml / L
X_A = 0.95

-r_A =	0.1C_A
	1 + 0.5C_A

(ii) V =	v₀C_AOX_A
		0.1C_A
		1 + 0.5C_A

further C_A = C_AO (1 – X_A)

∴ V =	v₀C_AOX_A
		C_AO (1 – X_A)
		1 + 0.5C_AO(1 – X_A)

Putting values & solve
V = 4987.5 L